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Remove pycurl 

It is now present and maintained in meta-python.

BugzID: 74466
This commit is contained in:
Alexandre Bard 2021-08-26 16:05:44 +02:00
parent 3d4f6a35f8
commit f2c2b75919
2 changed files with 0 additions and 30 deletions
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28
recipes-devtools/python/python-pycurl.inc
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@ -1,28 +0,0 @@
SUMMARY = "A Python Interface To The cURL library"
DESCRIPTION = "\
PycURL is a Python interface to libcurl, the multiprotocol file \
transfer library. Similarly to the urllib Python module, PycURL can \
be used to fetch objects identified by a URL from a Python program \
"
SECTION = "devel/python"
HOMEPAGE = "http://pycurl.io/"
LICENSE = "LGPLv2 | MIT"
LIC_FILES_CHKSUM = " \
file://COPYING-LGPL;md5=4fbd65380cdd255951079008b364516c \
file://COPYING-MIT;md5=2df767ed35d8ea83de4a93feb55e7815 \
"
SRC_URI[md5sum] = "f0ed4c805e8bec734990e2e0ee78568e"
SRC_URI[sha256sum] = "6f08330c5cf79fa8ef68b9912b9901db7ffd34b63e225dce74db56bb21deda8e"
inherit pypi
PYPI_PACKAGE = "pycurl"
PYCURL_SSL_LIBRARY ??= "openssl"
export PYCURL_SSL_LIBRARY
DEPENDS = "\
curl \
${PYTHON_PN}\
"

2
recipes-devtools/python/python3-pycurl_7.43.0.3.bb
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@ -1,2 +0,0 @@
inherit setuptools3
require python-pycurl.inc