Remove pycurl

It is now present and maintained in meta-python.

BugzID: 74466

recipes-devtools/python/python-pycurl.inc

@@ -1,28 +0,0 @@
-SUMMARY = "A Python Interface To The cURL library"
-DESCRIPTION = "\
-PycURL is a Python interface to libcurl, the multiprotocol file \
-transfer library. Similarly to the urllib Python module, PycURL can \
-be used to fetch objects identified by a URL from a Python program \
-"
-SECTION = "devel/python"
-HOMEPAGE = "http://pycurl.io/"
-
-LICENSE = "LGPLv2 | MIT"
-LIC_FILES_CHKSUM = " \
-    file://COPYING-LGPL;md5=4fbd65380cdd255951079008b364516c \
-    file://COPYING-MIT;md5=2df767ed35d8ea83de4a93feb55e7815 \
-"
-
-SRC_URI[md5sum] = "f0ed4c805e8bec734990e2e0ee78568e"
-SRC_URI[sha256sum] = "6f08330c5cf79fa8ef68b9912b9901db7ffd34b63e225dce74db56bb21deda8e"
-
-inherit pypi
-
-PYPI_PACKAGE = "pycurl"
-PYCURL_SSL_LIBRARY ??= "openssl"
-export PYCURL_SSL_LIBRARY 
-
-DEPENDS = "\
-    curl \
-    ${PYTHON_PN}\
-"

recipes-devtools/python/python3-pycurl_7.43.0.3.bb

@@ -1,2 +0,0 @@
-inherit setuptools3
-require python-pycurl.inc